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Friday, June 3, 2016

Pembahasan Mat IPA kode 248 SBMPTN 2016 - Bag2

Pembahasan Matematika IPA kode 248 SBMPTN 2016 - Bagian 2


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Soal no.4



a2 + b2  = |OO'|2



Soal no.5
α adalah sudut antara bidang MNP dan garis PB.

BD=3√2
MN2 = MD2 + DN2 → MN = 2√2
Misalkan Q adalah perpotongan BD dan MN, maka DQ=√2 dan BQ=2√2

Perhatikan ∆BDP



Soal no.6
f(–x) = f(x) dan g(–x) = g(x)

f(x)(x – 1) : (x2 – 2x – 3)
f(–1)(–2) = –1 + 3     
f(3)(3 – 1) = 3 + 3   →  f(3).2 = 6   


→   f(1) = f(–1) = –1
→   f(3) = f(–3) = 3

(x + 2)g(x) :  x2 + 2x – 3   →   sisa x + 5
g(1)(1 + 2) = 1 + 5    →    g(1) = g(–1) = 2
g(–3)(–3 + 2) = –3 + 5 →   g(–3) = g(3) = –2

xf(x)g(x) : (x2 + 4x + 3) → s(x) = ax + b
x = –1     →    –1.f(–1).g(–1) = –a + b   
x = –3     →    –3.f(–3).g(–3) = –3a + b


→  –a + b   = 2
→  –3a + b = 18    
        2a = –16  → a = –8
          b = –6
s(x) = –8x – 6

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